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8p^2-33p-35=0
a = 8; b = -33; c = -35;
Δ = b2-4ac
Δ = -332-4·8·(-35)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-47}{2*8}=\frac{-14}{16} =-7/8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+47}{2*8}=\frac{80}{16} =5 $
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